(x^2-2)/(x)-5=(2x-2)/x

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Solution for (x^2-2)/(x)-5=(2x-2)/x equation:


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

(x^2-2)/x-5 = (2*x-2)/x // - (2*x-2)/x

(x^2-2)/x-((2*x-2)/x)-5 = 0

(x^2-2)/x+(-1*(2*x-2))/x-5 = 0

(x^2-2)/x+(-1*(2*x-2))/x+(-5*x)/x = 0

x^2-1*(2*x-2)-5*x-2 = 0

x^2-2*x-5*x = 0

x^2-7*x = 0

x^2-7*x = 0

x*(x-7) = 0

x-7 = 0 // + 7

x = 7

x*(x-7) = 0

(x*(x-7))/x = 0

(x*(x-7))/x = 0 // * x

x*(x-7) = 0

( x-7 )

x-7 = 0 // + 7

x = 7

( x )

x = 0

x in { 0}

x = 7

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